3z(z+2)=3z^2+6z-3

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Solution for 3z(z+2)=3z^2+6z-3 equation:


Simplifying
3z(z + 2) = 3z2 + 6z + -3

Reorder the terms:
3z(2 + z) = 3z2 + 6z + -3
(2 * 3z + z * 3z) = 3z2 + 6z + -3
(6z + 3z2) = 3z2 + 6z + -3

Reorder the terms:
6z + 3z2 = -3 + 6z + 3z2

Add '-6z' to each side of the equation.
6z + -6z + 3z2 = -3 + 6z + -6z + 3z2

Combine like terms: 6z + -6z = 0
0 + 3z2 = -3 + 6z + -6z + 3z2
3z2 = -3 + 6z + -6z + 3z2

Combine like terms: 6z + -6z = 0
3z2 = -3 + 0 + 3z2
3z2 = -3 + 3z2

Add '-3z2' to each side of the equation.
3z2 + -3z2 = -3 + 3z2 + -3z2

Combine like terms: 3z2 + -3z2 = 0
0 = -3 + 3z2 + -3z2

Combine like terms: 3z2 + -3z2 = 0
0 = -3 + 0
0 = -3

Solving
0 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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